The term “Experimental School” for about twenty years has ceased to be literal. The children who go to these schools do not even have special books. schools nor is any entirely new and radical method of teaching tried in them, while in the others, the so-called non-experimental schools, one would proceed with some earlier system and make the necessary comparisons.
Today, in my opinion, an experiment for a completely different school model here in Greece would be to test how much of the curriculum could be assigned to sources that come directly from the Internet. And to go further, it would be worth looking for parents who allow their children to be taught with material that comes solely from the Internet.
It is sure that a day will soon come when employers will not ask if someone has a high school, high school or even elementary school diploma, but will choose the one whose knowledge is best suited for the job offered. So someone who hasn’t attended a single day of some kind of school with teachers will be able to get the job. This will not be good for society, as completely one-sided (and one-sided) minded people will emerge, which we will have to prevent. As; Creating an educational alloy over time where there will definitely be a human-educator but with different tasks and powers than today. Instead of a bodyguard, you will be a facilitator and guide for various types of “knowledge packs” plucked mostly for free from the Internet.
In this way, new types of schools will inevitably appear, as has already begun to occur in other countries. It is well known that, especially for Mathematics, there are now so many addresses on the Internet where one can be taught that one’s main problem will be where to start and how to proceed (so the illustrated guide is needed here too). And it’s not just the now famous Chan Academy.
The reason for the above was given to me by the fact that during the holidays I fell completely by chance on a website dedicated to Geometry and quite aptly called “For Geometry Romantics”.
1. Entering May, what more appropriate than this: In a bouquet we have put red, white and blue flowers. The sum of the reds and whites is 100, while the sum of the whites and blues is 53. The blues and reds are less than 53. How many of each type do we have?
2. Ten bottles of pills are received from a pharmacist with a note from the company that in 9 bottles the pills weigh 5 grams each but in the tenth they weigh 6 grams each. He doesn’t know what it is and instead of weighing one of each he does something else and finds out which bottle it is with a single weighing. As; If you are brought 6 bottles and told that more than one contains 6 gram pills, how will you know which ones by weighing again?
The answers to the previous questionnaires.
1. These days, those without their own plane are forced to cram overbooked flights. In one of them, 100 people had tickets for 100 correspondingly numbered seats on a flight. However, the first person on the plane could not find his ticket and due to Easter, he was allowed to sit wherever he wanted. Others entering would find their own seat or take another if theirs was occupied by a fellow traveler. What is the probability that the last person to enter sits in the seat that writes her ticket? If the first passenger chooses seat number 1, that is, theirs, and all the others occupy the seat that appears on their ticket, so does the last one. But if the first one sits in seat No. 100, then the second one will not sit in his seat. Now let’s say the first person sat in seat 47. Then passengers numbered 2 through 46 will sit in their seats. The passenger with ticket no. 47 has to choose between seats 1, 100 or one higher than 47. If he chooses no. 1, the last person will sit in his seat, no. 100. If he chooses no. 100, the last person will not will sit in his place. If you choose another one that will be above No. 47, we repeat the same reasoning. Thus we arrive at the end that for the last one there will have been the number 1 or the number 100 with equal probability, that is, 50%, for each one.
2. Two small boats carrying passengers and goods cross a river vertically at constant but different speeds. Starting from a different bank, each one at the beginning of the day is at a distance of 720 meters from a bank. Arriving at the other shore, each one unloads and after 10 minutes leaves for the opposite side. Now they are at a distance of 400 meters from the other shore, not the distance we measured before. How wide is the river? Let us call P the width of the river. In their first meeting they have sailed T distances of 720 and (Π-720) in the same period of time. If their speeds are for the slower ship v1=(720/T) and v2=([(Π-720)/Τ)] for the fastest, then (v2/v1)=[(Π-720)/720]. In their second meeting, the slower boat has covered a distance (Π+400) and the faster one (2Π−400). So (v2/v1)=[( 2Π-400)/ (Π+400)]. We equate and arrive at Π(Π-1760)=0. We reject Π=0, so Π=1760.
El Paso print edition